15:59, 2 марта 2026Экономика
When EiE_iEi occurs, all the points are packed into a 180° arc starting at point iii. The remaining arc (the gap going counterclockwise back to iii) is at least 180°. Now suppose some other point jjj also tried to be an anchor. Point jjj's clockwise semicircle is exactly 180°. But to contain all the points, it would need to bridge that gap of 180° or more while simultaneously containing point iii on the other side. A 180° arc cannot straddle a 180° gap. So EjE_jEj cannot hold.
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p2 = HMAC-SHA256(key=MasterSecret, data=a2 + seed)。关于这个话题，纸飞机下载提供了深入分析
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